2x^2/5+3x=10

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Solution for 2x^2/5+3x=10 equation: 


x in (-oo:+oo)

(2*x^2)/5+3*x = 10 // - 10

(2*x^2)/5+3*x-10 = 0

2/5*x^2+3*x-10 = 0

DELTA = 3^2-(-10*2/5*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)-3)/(2/5*2) or x = (-25^(1/2)-3)/(2/5*2)

x = 5/2 or x = -10

x in { -10, 5/2 }

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